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paultoole

Help with a small calculation

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Can someone please help me with a calculation - Math was never my best subject.

12ft mini/mega tree with 8ft diameter....what is the length from top to bottom outer ring?

Sorry to ask such a simple question, i just cant get my head around it.

Cheers!

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Answer is 12.65' by the way.

Assuming the ring is laying on the ground (which is what we'd have to assume since no base height is given).

The 'math' is a simple use of the Pythagorean theorem: We know the base of the triangle (the radius = 1/2 the diameter = 4'), the height of the triangle, (12') and we're looking for the hypotenuse.

Pythagorean theorem says a^2 + b^2 = c^2 (where c is the hypotenuse), so solve for c:

c^2 = 4^2 + 12^2 ->

c^2 = 16 + 144 ->

c^2 = 160 ->

c = sqrt( 160 ) ->

c = 12.65

If your base is elevated slightly from the ground, simply subtract that height from the 12' and redo the math above.

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If you have excel or some other spread sheet program......This spiral tree calculator also has all the mega tree calcs in it as well.

Answer is 12.65' by the way.

Great Calculator program. I am planning a spiral tree this year and this make the calculation easier!

KEN

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There is also this option available, The Spiral String Length Calculator or SSLC. A free and useful program that doesn't require a spreadsheet.

Download Spiral String Length Calculator

OK, maybe I'm missing something. Here it goes. I used the calculator, here's what I got. Am I missing something?

Inputs :

Top Diameter - 6 Inches (I assume the diameter of the traveler)

Bottom Diameter - 84 Inches

Height - 300 Inches

Number of Spirals - 32 (I assumed the number of strings???)

Here's the outputs :

Spiral Spacing - 9.38 Inches

Wire Length - 4523.89 Inches!!!! What the????

Tree Angle - 7.41 Inches

SO, did I miss something? Thanks all!

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Assuming the ring is laying on the ground (which is what we'd have to assume since no base height is given).

The 'math' is a simple use of the Pythagorean theorem: We know the base of the triangle (the radius = 1/2 the diameter = 4'), the height of the triangle, (12') and we're looking for the hypotenuse.

Pythagorean theorem says a^2 + b^2 = c^2 (where c is the hypotenuse), so solve for c:

c^2 = 4^2 + 12^2 ->

c^2 = 16 + 144 ->

c^2 = 160 ->

c = sqrt( 160 ) ->

c = 12.65

If your base is elevated slightly from the ground, simply subtract that height from the 12' and redo the math above.

I read this. What comes to mind is the "teacher" from Charlie Brown. Waaa waaaa waaaa waaaa waa waaaaa wa wa waaaa wa waaaaaaa.

OK. I do understand it - I just had to say that though...

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Assuming the ring is laying on the ground (which is what we'd have to assume since no base height is given).

The 'math' is a simple use of the Pythagorean theorem: We know the base of the triangle (the radius = 1/2 the diameter = 4'), the height of the triangle, (12') and we're looking for the hypotenuse.

Pythagorean theorem says a^2 + b^2 = c^2 (where c is the hypotenuse), so solve for c:

c^2 = 4^2 + 12^2 ->

c^2 = 16 + 144 ->

c^2 = 160 ->

c = sqrt( 160 ) ->

c = 12.65

If your base is elevated slightly from the ground, simply subtract that height from the 12' and redo the math above.

X2. Exactly what I done.

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I assume a spiral tree so using: http://www.lightsonsixth.com/stuff/spiraltreespreadsheet-97.xls

If I plug in 300 inches (25 feet) tall, diameter of 84 inches (7 feet) and assuming just 1 turn for a spiral tree, I get 330" (27.53 feet). Whatever you get, I would expect it just a bit larger number than the height.

Did you convert everything to feet?

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I assume a spiral tree so using: http://www.lightsonsixth.com/stuff/spiraltreespreadsheet-97.xls

If I plug in 300 inches (25 feet) tall, diameter of 84 inches (7 feet) and assuming just 1 turn for a spiral tree, I get 330" (27.53 feet). Whatever you get, I would expect it just a bit larger number than the height.

Did you convert everything to feet?

First, Yes I know 300 inches is 25 feet, that is the height of my tree, not 12 feet. After converting everything to feet, according to the "Program" not the Spreadsheet, my wire length is 376 Feet! That is what is hanging me up. Is this the total wire length for all guy wires combined? Maybe I'm just too ignorant to figure it out. Guess I'll stick to the Spreadsheet, thought the program might be easier.

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Just to help people out with the spiral tree, the string length is not real critical. Just keep spiraling until you run out of lights. But as an easy guess-timate, the light string should be about 25% to 30% longer than your cone wires. For example, if you have a 17ft tree (topper to base ring), a standard 70ct string (24ft) works out perfectly (1.5 turns)...

Try it in your calculators - it's pretty close...

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I think your error is number of spirals, most use like 1.5, I think its the number of times around your tree, so using 32 trips around (spirals) you are going to need a long string of lights

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